Split a string with any whitespace chars as delimiters?

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Something in the lines ofmyString.split("\s+");This groups all white spaces as a delimiter.So if I have the string:"Hello[space][tab]World"This should yield the strings "Hello" and "World" and omit the empty space between the [space] and the [tab].As VonC pointed out, the backslash should be escaped, because Java would first try to escape the string to a special character, and send that to be parsed. What you want, is the literal "\s", which means, you need to pass "\s". It can get a bit confusing.The \s is equivalent to [ \t\n\x0B\f\r]

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Split a string with any whitespace chars as delimiters?

Anonymous User

Can you answer this question?

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